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(B) Dispersive power $(\omega)$ is defined as the ratio of angular dispersion to the mean deviation.Mathematically, $\omega = \frac{\delta_2 - \delta_

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(B) Dispersive power $(\omega)$ is defined as the ratio of angular dispersion to the mean deviation.Mathematically, $\omega = \frac{\delta_2 - \delta_1}{\delta_{avg}}$, where $\delta_2$ and $\delta_1$ are the deviations of the extreme wavelengths and $\delta_{avg}$ is the deviation of the mean wavelength.Visually, the dispersive power is proportional to the angular spread between the extreme rays ($\lambda_1$ and $\lambda_2$) relative to the deviation of the mean ray $(\lambda_{avg})$.In diagram $B$, the angular separation between the rays corresponding to $\lambda_1$ and $\lambda_2$ is the largest relative to the deviation of the mean ray $\lambda_{avg}$.Therefore, diagram $B$ represents the case with the maximum dispersive power.

Consider the four different cases of dispersion of a light ray which has all the wavelengths from ${\lambda _1}$ to ${\lambda _2}$ (where ${\lambda _1} > {\lambda _2}$). The dotted line represents the light ray of wavelength ${\lambda _{avg}}$. Which ray diagram shows the maximum dispersive power?

Similar Questions

The refractive index of the material of the prism for violet colour is $1.69$ and that for red is $1.65$. If the refractive index for the mean colour is $1.66$,calculate the dispersive power of the material of the prism.

What is a dispersive medium?

Mention the constituent colors of white light.

If the refractive indices of crown glass for red,yellow,and violet colours are $1.5140, 1.5170$,and $1.5318$ respectively,and for flint glass these are $1.6434, 1.6499$,and $1.6852$ respectively,then the dispersive powers for crown and flint glass are respectively:

The deviations caused in red,yellow,and violet colors for a crown glass prism are $2.84^\circ$,$3.28^\circ$,and $3.72^\circ$ respectively. The dispersive power of the prism material is:

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